Question

The displacement *x* (in *metre*) of a particle in, simple harmonic motion is related to time *t* (in seconds) as

x = 0.01 cos (πt+π4)

The frequency of the motion will be

0.5 Hz

1.0 Hz

πHz

Solution

The correct option is **A**

0.5 Hz

Comparing given equation with standard equation,

x = a cos (ωt + ϕ), We get , a = 0.01 and ω=π

⇒2πn=π⇒n=0.5hz

Suggest corrections

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